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72w^2+35w+3=0
a = 72; b = 35; c = +3;
Δ = b2-4ac
Δ = 352-4·72·3
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-19}{2*72}=\frac{-54}{144} =-3/8 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+19}{2*72}=\frac{-16}{144} =-1/9 $
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